Let x the number of pounds of the high-quality bean used in the mix, and y the number of pounds of the cheaper bean, then we can set the following system of equations:
![\begin{gathered} x+y=150 \\ 5x+3y=150\cdot4.33 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4kt81id9dnjvmbpiqxqo3yj7zl81az5w1j.png)
Solving the first equation for x, and substituting in the second equation we get:
![\begin{gathered} x=150-y \\ 5(150-y)+3y=150\cdot4.33 \\ 750-5y+3y=649.5 \\ 750-649.5=2y \\ y=(100.5)/(2) \\ y=50.25\approx50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/weq28ym5oz9jlb0b5drjzy0o301gbz7j2d.png)
Therefore, x=150-50.25=99.75≈100.
Answer: 50 pounds of the cheap bean should be blended and 100 pounds of the high-quality bean should be blended.