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Use the diagram to complete the statement.-74A 3G B530)45°C С412/F9ECF=

User Vaviloff
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From the triangle CDF, we can see that it is an isosceles triangle.


\begin{gathered} \\ \sin \text{ 45 =}\frac{CF}{12\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{CF}{12\sqrt[]{2}} \\ CF\text{ = 12} \end{gathered}

User Ashrith Reddy
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