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Factorise 3x⁴-4y⁴ completely
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Factorise 3x⁴-4y⁴ completely

User DrWaky
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17 votes

Answer:

Explanation:


3x^4-4y^4\\=(√(3)x^2)^2-(2y^2)^2)\\=(√(3)x^2+2y^2)(√(3)x^2-2y^2)\\=(√(3) x^(2) +2y^(2) )((3^{(1)/(4) } x)^2-(√(2) y)^(2) )\\=(√(3) x^(2) +2y^(2) )(3^{(1)/(4) } x+√(2) y)(3^{(1)/(4) } x-√(2) y)

User Charming Robot
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