Answer:
Name of the figure: Cone
Lateral Area: 770.66
Total Surface Area: 1084.82
Step-by-step explanation:
We identify the figure as a cone.
The lateral surface area of a cone is given by
![A_L=\pi r√(r^2+h^2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/l50orrhh1gp1luem50j1h5vu9ylrrlj2kv.png)
The total surface area includes the area of the base as well.
Since the area of the base is
![A_B=\pi r^2](https://img.qammunity.org/2023/formulas/mathematics/college/3pw8m32qb00jmk64h03d88uq8jjiyity4k.png)
The total surface area then is
![A_(tot)=A_L+A_B=\pi r√(r^2+h^2)+\pi r^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/48686vgbf9xzndm71b3lcdv0w32dzmuvcn.png)
where
r = radius of the base
h = height of the cone.
Now in our case
r = 20/2 = 10
h = 22.4
therefore,
![A_L=\pi(10)√((10)^2+(22.4)^2)=770.66](https://img.qammunity.org/2023/formulas/mathematics/high-school/sztbqi37j1ygqt8f0tc8p6w04bm77owiiv.png)
![A_B=\pi(10)^2=314.16](https://img.qammunity.org/2023/formulas/mathematics/high-school/w2qzzk98ayohza0j39v1wv5izw6ajppf1j.png)
Therefore,
![A_(tot)=A_L+A_B=770.66+314.16](https://img.qammunity.org/2023/formulas/mathematics/high-school/tt0f6ddxldb16nszr21uns6nrvxwobhtxw.png)
![\Rightarrow\boxed{A_(tot)=1084.82.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/i3nx5fr32dw4fhbftchmf9zynkiecfh4s3.png)
Hence, to summerise,
Name of the figure: Cone
Lateral Area: 770.66
Total Surface Area: 1084.82