Question

I need 5 points plotted. 2 to the left of vertex, the vertex, and 2 to the right of vertex. the graph ONLY GOES UP TO 14. please hurry am timed

Answer 1

Given:

`y=x^2-4x+3`

To graph the given equation, we put any values of x to find y values as shown below:

Example:

Let:

x=0

So,

`\begin{gathered} y=x^2-4x+3 \\ y=(0)^2-4(0)+3 \\ \text{Simplify} \\ y=3 \end{gathered}`

This means that when x=0, the value of y is 3. It can also be noted that the point is (0,3). We follow the same process to get the other points on the parabola. We must also remember that vertex is the lowest point or the highest point of the graph.

The graph of the equation is shown below: