Question

Travis made a business trip of 305.5 miles. He averaged 49 mph for the first part of the trip and 61 mph for the second part. If the trip took 5.5 hours, how long did he travel at each rate ?

Answer 1

We are given the following details:

Travis travelled a distance of 305.5 miles

He travelled 49 mph for the first part of the trip

He travelled 61 mph for the second part of the trip

The trip took 5.5 hours

We will calculate how long he travelled at each rate as shown below:

`\begin{gathered} Let^(\prime)s\text{ assume that }the\text{ number of hours travelled during the second part of the trip is ''x'':} \\ \Rightarrow61(x)+49(5.5-x)=305.5 \\ 61(x)+49(5.5-x)=305.5 \\ \text{Expanding the bracket, we have:} \\ 61x+269.5-49x=305.5 \\ \text{Put like terms together, we have:} \\ 61x-49x=305.5-269.5 \\ 12x=36 \\ \text{Divide both sides by ''12'', we have:} \\ x=(36)/(12)=3 \\ x=3 \end{gathered}`

It means the second part of the trip took 3 hours while the first part of the trip took 2.5 hours

Therefore, Travis travelled at 49 mph for 2.5 hours & travelled at 61 mph for 3 hours