Answer:
15.3 g
Step-by-step explanation:
- Fe₂O₃ (s) + 2Al (s) → 3Fe (l) + Al₂O₃ (s)
First we convert 8.0 grams of aluminum into moles, using its molar mass:
- 8.0 g Al ÷ 27 g/mol = 0.30 mol Al
Then we convert 0.30 moles of aluminum into moles of aluminum oxide, using the stoichiometric coefficients:
- 0.30 mol Al *
= 0.15 mol Al₂O₃
Finally we convert 0.15 moles of Al₂O₃ into grams, using its molar mass:
- 0.15 mol Al₂O₃ * 102 g/mol = 15.3 g Al₂O₃