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First box options are -22-1/21/2second box options are -55-33Third boxes options are -2-112fourth options -2-121

First box options are -22-1/21/2second box options are -55-33Third boxes options are-example-1
User Adrian Cox
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DEFINITIONS AND FORMULAS

The equation of a straight line can be written in the slope-intercept form to be:


y=mx+b

where m is the slope and b is the y-intercept.

The formula to calculate the slope is given to be:


m=(y_2-y_1)/(x_2-x_1)

SOLUTION

Table 1: Two points can be picked from the table as shown below


\begin{gathered} (x_1,y_1)=(-5,10) \\ (x_2,y_2)=(0,0) \end{gathered}

Therefore, the slope is calculated to be:


m=(0-10)/(0-(-5))=-(10)/(5)=-2

The y-intercept is the value on the y-axis when the x-axis is 0. Therefore:


\begin{gathered} At \\ x=0,y=0 \\ \therefore \\ b=0 \end{gathered}

Therefore, the equation of the first table is:


y=-2x

Table 2: Two points can be picked from the table as shown below


\begin{gathered} (x_1,y_1)=(-8,-11) \\ (x_2,y_2)=(1,-2) \end{gathered}

Therefore, the slope is calculated to be:


m=(-2-(-11))/(1-(-8))=(-2+11)/(1+8)=(11)/(11)=1

Therefore, the equation of the line is:


y=x+b

To find the value of b, we need to substitute one of the ordered pairs in the table into the equation and solve for b:


\begin{gathered} \text{Using} \\ (x,y)=(1,-2) \\ \therefore \\ -2=1+b \\ b=-2-1 \\ b=-3 \end{gathered}

Therefore, the equation of the second table is:


y=x-3

To get the solution to the system of equations, we can plot the graphs of the equations. This is shown below:

The solution to the system is the point where both graphs intersect.

Therefore, the solution to the system is:


(x,y)=(1,-2)

ANSWERS

The equation of the first system is:


y=-2x

The equation of the second system is:


y=x-3

The solution to the system is:


(1,-2)

First box options are -22-1/21/2second box options are -55-33Third boxes options are-example-1
User Lightlike
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