Question

I need some help with math

Answer 1

`3x^2-14x=-15`

start by bringing all terms to the left of the equation

`3x^2-14x+15=0`

multiply the equation by the leading coefficient

`9x^2-42x+45=0`

use a substitution u=3x, because it is the square root of the first term,

`u^2-14u+45=0`

factor using the solutions -9 and -5 since multiplied together they give a result of 45 and added together -14

`(u-9)(u-5)`

replace with the substitution used

`(3x-9)(3x-5)`

then, divide by the 3 we multiplied in the first step

`(x-3)(3x-5)`

Answer:

`(x-3)(3x-5)`
`\begin{gathered} 3x^2-5x-9x+15 \\ 3x^2-14x+15 \end{gathered}`