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Explain how you would determine the horizontal asymptote of f(x) = 2x-1 / 50-x

User Twillouer
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\begin{gathered} f(x)\text{ =}(2x-1)/(50-x) \\ To\det er\min e\text{ the horizontal asymptote, w}e\text{ compare the degre}e\text{ of x in the numerator and denominator} \\ \end{gathered}

The degree of x in the numerator is 1 and the degree of x in the denominator is 1 as well

There we go ahead to divide the coefficient of x in the numerator by that in the denominator

The coefficient of x in the numerator is 2 and the coefficient of x in the denominator is -1

Therefore


\begin{gathered} (2)/(-1) \\ =-2 \end{gathered}

The horizontal asymptote is -2

User KevSheedy
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