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How many grams of ammonia would be produced from the reaction of 2.64 moles of hydrogen gas reacting with excess nitrogen?

How many grams of ammonia would be produced from the reaction of 2.64 moles of hydrogen-example-1
User Hsh
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2 Answers

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22 votes

Answer:

29.92g

Step-by-step explanation:

tell me if my answer is wrong

User Shu Ding
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2.64 moles of H₂, reacting with excess N₂, produce around 29.98 grams of NH₃ according to the stoichiometry of the balanced chemical equation.

To determine the grams of ammonia (NH₃) produced from 2.64 moles of hydrogen gas (H₂) reacting with excess nitrogen (N₂), we use the stoichiometry of the balanced equation:


N_2(g) + 3H_2(g)
2NH_3(g)

The balanced equation shows a 1:3 ratio between moles of hydrogen and moles of ammonia. Thus, for 2.64 moles of H₂, we can calculate the moles of NH₃ produced:

Moles of NH₃ = ((2.64 moles of H₂)/3)
* 2

Moles of NH₃
\approx 1.76

Next, we find the mass of NH₃ using its molar mass (approximately 17.03 g/mol):

Mass of NH₃ = Moles of NH₃
* Molar mass of NH₃

Mass of NH₃
\approx 1.76
* 17.03

Mass of NH₃
\approx 29.98 grams

Therefore, from 2.64 moles of H₂ reacting with excess N₂, approximately 29.98 grams of NH₃ would be produced.

User Stralep
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