Question

Solve for b2/3b+5=20−b

Answer 1

`(2)/(3)b+5=20-b`
`\begin{gathered} \text{Multiply through by 3 to remove the fraction} \\ 3*(2)/(3)b+3*5=3*20-3* b \end{gathered}`
`\begin{gathered} \text{Simplify the equation} \\ 2b+15=60-3b \\ \end{gathered}`
`\begin{gathered} \text{collect like terms} \\ 2b+3b=60-15 \end{gathered}`
`\begin{gathered} 5b=45 \\ \text{Divide both sides by 5} \end{gathered}`
`\begin{gathered} (5b)/(5)=(45)/(5) \\ b=9 \end{gathered}`

The value of b is 9