Question

Given the function k(x)=−lnx, which of the following functions has a graph identical to k(x)q(x)=lnxq(x)=ln(1x)q(x)=ln(−x)q(x)=3e−x−1

Answer 1

according to the properties of logarithms

`\begin{gathered} \ln ((1)/(x))=\ln (1)-\ln (x);\ln (1)=0 \\ \Rightarrow0-\ln (x) \\ \Rightarrow\ln ((1)/(x))=-\ln (x) \end{gathered}`

therefore, the answer is option 2