We are given the following equation in vector form:
![\begin{bmatrix}{5x} & {} \\ {20} & {}\end{bmatrix}=\begin{bmatrix}{3} & {} \\ {5y} & {}\end{bmatrix}](https://img.qammunity.org/2023/formulas/mathematics/high-school/1d4mse1hg2mpevbcprbqit3er6w3mxmz15.png)
To solve the equation we need to remember that two vectors are equal of the corresponding elements are equal. Therefore, we set equal the first elements:
![5x=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/riep5d6e99rsg9evlwufwq57spk3h6n79j.png)
Now, we divide both sides by 5:
![x=(3)/(5)](https://img.qammunity.org/2023/formulas/mathematics/high-school/ohh6lk8i5koynfn62xv9xktow5hsvkiwgr.png)
Now, we set equal the second elements:
![20=5y](https://img.qammunity.org/2023/formulas/mathematics/high-school/6yu3hqeihxxli3nyb0hqi1xdzx0t536pg2.png)
Now, we divide both sides by 5:
![\begin{gathered} (20)/(5)=y \\ \\ 4=y \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tpjknw3yhhbj09o6r81jfi8gtufiqke9iz.png)
Therefore, "x = 3/5" and "y = 4".