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There are 15 marbles in a bag.Two marbles are white, five are blue and eight are red.Find the probability of each event and write your answer as a fraction. I need the steps if possible

There are 15 marbles in a bag.Two marbles are white, five are blue and eight are red-example-1

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Given:

The total number of marbles in the bag, T=15.

The number of white marble, W=2.

The number of blue marbles, B=5.

The number of red marbles, R=8.

The probability of choosing a white marble is,


P(White)=(W)/(T)=(2)/(15)

The probability of choosing a blue marble is,


P(Blue)=(B)/(T)=(5)/(15)=(1)/(3)

The probability of choosing a red marble is,


P(Red)=(R)/(T)=(8)/(15)

The probability of choosing two reds in a row is a dependent event.

There are 8 red marbles in the bag. So, the probability of choosing a red in the first draw is,


P(\text{ Red in first draw)=}(8)/(15)

Since one red ball is drawn from the bag, there are only 7 red balls remaining in the bag. Also, there are only 14 balls remaining in the bag. So, the probability of choosing a red in the second draw is,


P(\operatorname{Re}d\text{ in the second draw)=}(7)/(14)

Now, the probability of choosing two reds in a draw is,


\begin{gathered} P(\text{Two reds in }a\text{ row)=}P(\operatorname{Re}d\text{ in first draw)}* P(\operatorname{Re}d\text{ in second draw)} \\ =(8)/(15)*(7)/(14) \\ =(28)/(105) \end{gathered}

User Moshe Quantz
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