Given:
The total number of marbles in the bag, T=15.
The number of white marble, W=2.
The number of blue marbles, B=5.
The number of red marbles, R=8.
The probability of choosing a white marble is,

The probability of choosing a blue marble is,

The probability of choosing a red marble is,

The probability of choosing two reds in a row is a dependent event.
There are 8 red marbles in the bag. So, the probability of choosing a red in the first draw is,

Since one red ball is drawn from the bag, there are only 7 red balls remaining in the bag. Also, there are only 14 balls remaining in the bag. So, the probability of choosing a red in the second draw is,
![P(\operatorname{Re}d\text{ in the second draw)=}(7)/(14)]()
Now, the probability of choosing two reds in a draw is,
![\begin{gathered} P(\text{Two reds in }a\text{ row)=}P(\operatorname{Re}d\text{ in first draw)}* P(\operatorname{Re}d\text{ in second draw)} \\ =(8)/(15)*(7)/(14) \\ =(28)/(105) \end{gathered}]()