The anwer is YES, let's see why:
![\begin{gathered} y^2=4-x^2 \\ y=\sqrt[]{4-x^2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dl6ixl0hhkty8dp23zm3g3bhdkse42y4b6.png)
If we solve for y, as in the second equation, we can see that "y" will have a value depending on which value "x" will take.
Actually, this is the meaning of function involving independent and dependent variables ( x and y, respectively)