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Does y^2=4-x^2 define y as a function of x?

User DeBorges
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The anwer is YES, let's see why:


\begin{gathered} y^2=4-x^2 \\ y=\sqrt[]{4-x^2} \end{gathered}

If we solve for y, as in the second equation, we can see that "y" will have a value depending on which value "x" will take.

Actually, this is the meaning of function involving independent and dependent variables ( x and y, respectively)

User Tanmay Delhikar
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