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X~(129.71,2.28) find the percent of her laps that are completed in less than 135 seconds

User TopaZ
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For this case we have the mean, which is 129.71 and the standard deviation 2.28. We need to first calculate the z value, which is given by the following expression:


z=\frac{x-\operatorname{mean}}{\sigma}
z=(135-129.71)/(2.28)=(5.29)/(2.28)=2.32017

Now we need to look at the z-table to determine the percentage that is less than 135. From there we obtain the following:


\text{percentage}=0.9898\cdot100\text{ \%=98.98 \%}

A total of 98.98% of her runs will be less than 135 seconds.

User Adrian Garner
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