Question

This is my Question... Triangle "A" has a base of 10in and a height of 12in. Triangle "B" has a height of 4in. What is the base?

Answer 1

`\text{Base = 3}(1)/(3)\text{ in (option A)}`

Step-by-step explanation:

We are not told if both triangles have same areas.

So we would be assuming the triangles are similiar triangles

One of the triangle's dimension:

Base = 10 in, height = 12 in

The 2nd triangle's dimension:

height = 4in, base = ?

We apply the ratio of the corresponding sides of the triangles:

base/height of 1st triangle = Base/Height 2nd triangle

`\begin{gathered} (10)/(12)=(Base)/(4) \\ 10*4=\text{ 12}* Base \end{gathered}`
`\begin{gathered} 40\text{ = 12Base} \\ \text{divide both sides by 12:} \\ \frac{40}{12\text{ }}=\text{ Base} \\ \text{Base = }(10)/(3) \\ \text{Base = 3}(1)/(3)\text{ in (option A)} \end{gathered}`