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Find the length of arc RS. Use 3.14 for a.Round to the nearest tenth.P6.48 inS7391500 650R[ ? JinEnter

Find the length of arc RS. Use 3.14 for a.Round to the nearest tenth.P6.48 inS7391500 650R-example-1

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SOLUTION

We want to solve the question below

We are told to find the length of arc RS.

We will use the formula for length of an arc that says


\begin{gathered} L=(\theta)/(360\degree)*2\pi r \\ where\text{ L = length of arc} \\ \theta=\text{ angle subtended at the center of arc RS = 150}\degree \\ \pi=3.14 \\ r=\text{ radius of the circle = 6.48 in} \end{gathered}

Substituting the values into the formula, we have


\begin{gathered} L=(150)/(360)*2*3.14*6.48 \\ L=(15*2*3.14*6.48)/(36) \\ L=(610.416)/(36) \\ L=16.956 \\ L=17.0\text{ to the nearest tenth } \end{gathered}

Hence the answer is 17.0 to the nearest tenth

Find the length of arc RS. Use 3.14 for a.Round to the nearest tenth.P6.48 inS7391500 650R-example-1
User Norbert Korny
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