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Determine whether the given ordered pair is a solution to the system of equations.5x−y =4 x+6y =2 Ordered pair: (4,0)

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Solution:

Given the system of equations:


\begin{gathered} 5x-y=-4\text{ -- equation 1} \\ x+6y=2\text{ --- equation 2} \end{gathered}

To determine if the ordered pair (4, 0) is a solution to the system of equations, we solve for x and y.

Thus, by the substitution method of solving simultaneous equations, we have

from equation 1,


\begin{gathered} make\text{ y the subject of formula,} \\ y=5x+4---\text{ equation 3} \end{gathered}

Substitute equation 3 into equation 2.

Thus, we have


\begin{gathered} x+6(5x+4)=2 \\ open\text{ parentheses,} \\ x+30x+24=2 \\ collect\text{ like terms,} \\ 31x=-22 \\ divide\text{ both sides by the coefficnet of x, which is 31} \\ (31x)/(31)=-(22)/(31) \\ \Rightarrow x=-(22)/(31) \end{gathered}

To solve for y, substitute the obtained value of x into equation 3.

Thus,


y=5(-(22)/(31))+4=(14)/(31)

Thus, the solution to the system of equations is


(x,y)\Rightarrow(-(22)/(31),(14)/(31))

Hence, the ordered pair (4, 0) is NOT a solution to the system of equations.

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