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Suppose that you are given a 200 gram sample of a radioactive substance with a half-life of 45 days. How many grams will be left after 360 days?

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Given:

The initial amount of the radioactive sample is,


m=200\text{ g}

The half-life is,


t_{(1)/(2)}=45\text{ days}

The total time span is,


t=360\text{ days}

To find:

How many grams will be left after 360 days?

Step-by-step explanation:

The number of half-life within the given time span is,


\begin{gathered} n=\frac{t}{t_{(1)/(2)}} \\ n=(360)/(45) \\ n=8 \end{gathered}

The sample left over after this time is,


\begin{gathered} m^(\prime)=m*((1)/(2))^n \\ =200*((1)/(2))^8 \\ =200*(1)/(256) \\ =0.78\text{ g} \end{gathered}

Hence, the leftover amount after the time is 0.78 g.

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