Question

M2E4(g) can be synthesized from M2E(g) and E2(g) at 200℃ as shown below. 2 M2E(g) + 3 E2(g) ⇌ 2 M2E4(g) ∆H < 0 Which of the following changes would result in more M2E(g) in the mixture after equilibrium is re-established?​

Answer 1

See explanation

Step-by-step explanation:

Now, let us consider the equation;

2 M2E(g) + 3 E2(g) ⇌ 2 M2E4(g) ∆H < 0

This means that the reaction is exothermic. The enthalpy change is negative (less than zero). An exothermic reaction is made to proceed in the forward reaction when the temperature is decreased. Hence increase in temperature leads to the equilibrium position shifting to the left (more M2E(g)) produced.

Also, when the pressure is decreased, the equilibrium position moves towards the left more (more M2E(g)) produced.