Let's understand 4 basic translation rules first:
Let parent function be f(x), so
1. h(x+a) would be f(x) translated a units left
2. h(x-a) would be f(x) translated a units right
3. h(x) + a would be f(x) translated a units up
4. h(x) - a would be f(x) translated a units down
As for reflection, the rules we would need to knw would be:
1. -f(x) would be f(x) replected in x axis
2. f(-x) would be f(x) reflected in y-axis
Now,
given
g is translated 2 units right, that would make f(x):
![\begin{gathered} g(x)=f(x-2)^{} \\ =(x-2)^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hpwa2tfw7i68fxnjr4uehck9du4p2plcfk.png)
Then,
g is translated 3 units up, so it would be:
![g(x)=(x-2)^2+3](https://img.qammunity.org/2023/formulas/mathematics/college/l7pigwxa47nki8w13a2i03lgsbcdjnexpd.png)
Last step is to reflect across y-axis.
This means put "-x" in place of x to get:
![\begin{gathered} (x-2)^2+3 \\ =(-x-2)^2+3 \\ =(x-2)^2+3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gajrpc71r9jtd7bdoptb0hgnfnrwe4l4bb.png)
Same thing.
To write the equation in the form wanted, we multiply:
![\begin{gathered} (x-2)^2+3 \\ =x^2-4x+4+3 \\ =x^2-4x+7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gx4qjpx0knnawh7day67v43x3numy8ds8d.png)
Note:
![(a-b)^2=a^2-2ab+b^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/wij5s4hl5c81m5e13tfkbmm8jk6ed6srgr.png)