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Find the values of x and y that makes each equation true. 9x–16i=(2y)i+18

User Hbaromega
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\begin{gathered} \text{From the given equation, the real part of the equation is} \\ 9x=18 \\ On\text{ solving the above real part} \\ x=(18)/(9) \\ x=2 \end{gathered}
\begin{gathered} Now,\text{ the imaginary part of the equation is} \\ -16=2y \\ \text{Solving for y in the imaginary part} \\ y=(-16)/(2) \\ y=-8 \end{gathered}

Hence the value of x is 2 and the value of y is -8

User Tristan G
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