Question

In ΔFGH, h = 9.6 inches, f = 2.5 inches and ∠G=78°. Find the length of g, to the nearest 10th of an inch.

Answer 1

Answer: 9.4

Explanation:

S.A.S.→Law of Cosines

a^2=b^2+c^2-2bc\cos A

g^2 = 9.6^2+2.5^2-2(9.6)(2.5)\cos 78

g^2 = 92.16+6.25-2(9.6)(2.5)(0.207912)

g^2 = 92.16+6.25-9.97976

g^2 = 88.43024

g=√88.43024 ≈9.404≈9.4

Answer 2

Answer:9.4

Explanation: