Question

(-2 3), (-7-7)Finding the distance formula

Answer 1

distance = 5√5

Step-by-step explanation:

The given points: (-2 3), (-7-7)

`\begin{gathered} \text{The distance formula = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ \end{gathered}`
`\begin{gathered} \text{ }(x_1,y_1)and^{}(x_2,y_2)^{}\text{ = }\mleft(-2,3\mright),(-7-7) \\ dis\tan ce\text{ = }\sqrt[]{(-7-3)^2+(-7-(-2))^2} \\ =\text{ }\sqrt[]{(-10)^2+(-7+2)^2}\text{ =}\sqrt[]{100+25} \\ =\sqrt[]{125} \end{gathered}`
`\begin{gathered} \text{Distance = }\sqrt[]{125}\text{ = }\sqrt[]{25*5} \\ \text{Distanc e= 5}\sqrt[]{5} \end{gathered}`