Question

I'm having some trouble with this questionsolve by completing the square

Answer 1

(x - 5)² = x² - 2*5*x + 5² = x² - 10x + 25

We have:

x² - 10x = -12

Adding 25 at both sides of the equal sign

x² - 10x + 25 = -12 + 25

(x - 5)² = 13

`x-5=\sqrt[]{13}`

The square root of 13 has two solutions, one positive and one negative, then:

`\begin{gathered} x-5=\sqrt[]{13} \\ x=\sqrt[]{13}+5 \\ or \\ x-5=-\sqrt[]{13} \\ x=-\sqrt[]{13}+5 \end{gathered}`