1 Answer

Ask a Question

Ryan Heathcote · Answer 1 · 2023-07-06T02:05:05+0000

We need to use a Z-score table for the following

a. P(z> 1,03) = 0.152

$P(Z=1.03)=0.8485\rightarrow P(Z>1.03)=1-0.8485=0.1515$

b. P(Z< -1.77) = 0.038

$P(Z=-1.77)=0.0384\rightarrow P(Z<-1.77)=0.0384$

c. P(0.58 < Z < 2.34) = 0.271

$\begin{gathered} P(Z=0.58)=0.7190, \\ P(Z=2.34)=0.9904 \\ \rightarrow P(0.58d. P(-1.35 < z < -0.59) = 0.189[tex]\begin{gathered} P(Z=-1.35)=0.0885 \\ P(Z=-0.59)=0.2776, \\ \rightarrow P(-1.35e. P(Z <0) = 0.500[tex]P(Z=0)=0.50\rightarrow P(Z<0)=0.50$

f. P(-2.15 < z < 1.34) = 0.894

[tex]\begin{gathered} P(Z=-2.15)=0.0158 \\ P(Z=1.34)=0.9099 \\ P(-2.15

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions