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Find the surface area of the polyhedron below. The area of each base is 65 cm2O A. 400 cm2O B. 130 cm?O c. 200 cm2O D. 330 cm2

Find the surface area of the polyhedron below. The area of each base is 65 cm2O A-example-1
User SnoProblem
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1 Answer

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Given: A polyhedron shown in the image

To Determine: The surface area of the polyhedron

Solution

It can be observed that the polyhedron has 6 faces and two base faces

Each of the sides are rectangle. The area of a rectangle can be calculated as


Area(rectangle)=length* width

So, for each of the 6 rectangular faces, the area is as calculated below


\begin{gathered} Area(Rectangle1)=4cm*10cm=40cm^2 \\ Area(Rectangle2)=3cm*10cm=30cm^2 \\ Area(Rectangle3)=2cm*10cm=20cm^2 \end{gathered}
\begin{gathered} Area(Rectangle4)=2cm*10cm=20cm^2 \\ Area(Rectangle5)=2cm*10cm=20cm^2 \\ Area(Rectangle6)=7cm*10cm=70cm^2 \end{gathered}

The area of the polyhedron is addition of all the areas of the rectangle and the two base area


\begin{gathered} Area(Polyhedron)=65cm^2+65cm^2+40cm^2+30cm^2+20cm^2+20cm^2+20cm^2+70cm^2 \\ =330cm^2 \end{gathered}

Hence, the area of the polyhedron is 330cm²

User Alexandrine
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