Question

Given the equation: 4Fe + 3O2 ---> 2Fe2O3How many molesof o2are needed to produce34.7g of Fe

Answer 1

Step 1: balance the equation.

The equation given is already balanced

`4Fe+3O_2\rightarrow2Fe_2O_3`

Step 2: Calculate the number of moles of Fe

n = m/M

n = 34.7 g/55,845 g/mol

n = 0.621 mol

Step 2: Use the stoichiometry to find moles of O2

The molar rato between Fe and O2 is 4:3

Therefore the number of moles O2 = 0.621 x (3/4) = 0.466 mol

The answer is 0.466 mol.