Question

6. You have 1.2 x 10^25 particles of CN. How many moles are present?

Answer 1

19.93 mol

Step-by-step explanation

Given:

The number of particles of CN = 1.2 x 10²⁵

What to find:

The number of moles of CN present in 1.2 x 10²⁵ particles of CN.

Step-by-step solution:

According to Avogadro, 1 mole of CN has 6.022 x 10²³ particles.

Therefore, the number of moles of CN present in 1.2 x 10²⁵ particles of CN will be:

`\frac{1\text{ }mol*1.2*10^(25)\text{ }particles}{6.022*10^(23)\text{ }particles}=19.93\text{ }mol`

The number of moles of CN present in 1.2 x 10²⁵ particles of CN = 19.93 mol.