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Please help me find the sum of this series: a1: 6, r=3, n=8

Please help me find the sum of this series: a1: 6, r=3, n=8-example-1
User John Sharp
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1 Answer

4 votes

Given:


\begin{gathered} a_1=6 \\ r=3 \\ n=8 \end{gathered}

To find: The sum of the geometric series

Since,


r=3>1

The sum formula for the geometric series is,


S_n=(a_1(r^n-1))/(r-1)

Substituting the given values, we get


\begin{gathered} S_n=(6(3^8-1))/((3-1)) \\ =(6(6561-1))/(2) \\ =3(6560) \\ =19680 \end{gathered}

Thus, the sum of the given series for 8 terms is 19680.

Final answer: The sum is,


S_n=19680

User Nitin Srivastava
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