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two jets leave an air base at the same time and travel in opposite directions. one jet travels 99 mi/h slower than the other. if the two jets are 11,352 miles apart after 8 hours what is the rate of each jet?

User Bsoist
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1 Answer

7 votes

1) Gathering the data

Speed Jet 1: x

Speed Jet 2: x-99

Distance between them: 11,532 miles

After 8 hours

What is the rate of each jet?​

2) Let's write an equation, relating to all of this information. The distance, the speed. Thinking of V =Δs/ *Δt ⇒Δs = V*Δt

11532 = (x+x-99) *8

11532=(2x -99)8

11532 =16x -792

11532+792=16x

12324=16x Divide both sides by

x= 770.25 mph

2.2 The speed of jet 1 = 770.25 mph jet 2 : 671.25 mph

User Jacob Lange
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