Question

Two 4 Ω resistors are connected in parallel and then connected in series with a 3 Ω resistor. What is the equivalent resistance of this combination?Group of answer choices7 Ω5 Ω1.20 Ω11 Ω

Answer 1

Given,

The resistance connected in parallel, R=4 Ω

The resistor connected in series, r=3 Ω

The equivalent resistance of two given resistors connected in parallel is given by,

`\begin{gathered} R_0=(R* R)/(R+R) \\ =(R)/(2) \end{gathered}`

Thus the total equivalent resistance of the given combination of resistance is given by,

`\begin{gathered} R_(eq)=R_0+r \\ =(R)/(2)+r \end{gathered}`

On substituting the known values,

`\begin{gathered} R_(eq)=(4)/(2)+3 \\ =5\text{ }\Omega \end{gathered}`

Therefore the equivalent resistance of the given combination is 5 Ω

Thus the correct answer is option B.