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6x² + 5x-7=0What are the solutions to the given equation?A)-5 + 25 + 16812B)-6 + 25 + 16812C)-5 + 36 - 16812-6 + V36168D)12

1 Answer

3 votes

If we had an equation with the form:


ax^2+bx+c=0

The solutions can be calculated as:


\begin{gathered} x_1=(-b+√(b^2-4ac))/(2a) \\ x_2=(-b-√(b^2-4ac))/(2a) \end{gathered}

User Dshockley
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