Data:
• B = 70°
,
• b = 19ft
,
• C = 90°
Procedure:
• Finding the angles
We know that C = 90° as the image shows the symbols. Also, we know that the sum of the interior angles of a triangle are 180°. Then, to get A we have to do the following:

Isolating for A:

Replacing the values we know:


• Finding side ,a
Using trigonometric functions, we can get a.

As we already know the value of A and b, we can isolate for a:

Replacing the values:

• Finding side ,c
Finally, using the Pythagorean Theorem, we can calculate c:

Isolating for c:
![c=\sqrt[]{a^2+b^2}](https://img.qammunity.org/2023/formulas/mathematics/college/6uwqakmkjq6nua21bpopztkrf20jt2flji.png)
Replacing the values:
![c=\sqrt[]{6.92^2+19^2}](https://img.qammunity.org/2023/formulas/mathematics/college/eh2ux8vuo829rivkkl043ras8bze0e8wbb.png)

Answer:
• A = 20°
• a = 6.92 ft
,
• c = 20.22 ft