Question

Solve each equation with the quadratic formula ! Question 3 ?

Answer 1

`x^2\text{ - 2x + 1 = 0}`

The quadratic formula is given by:

`\frac{-b\text{ + }\pm\text{ }\sqrt[]{b^2-4ac\text{ }}}{2a}`

Step 1: name the coefficients

a = 1, b = -2, c = 1

Step 2: substitute the vales of the coefficient into the equation

`\frac{-2\text{ }\pm\sqrt[]{(-2)^2\text{ - 4 x 1 x 1}}}{2\text{ x 1}}`

`\begin{gathered} \frac{-2\text{ }\pm\sqrt[]{4\text{ - 4 }}}{2\text{ x 1}} \\ \\ \frac{-2\text{ }\pm\text{ 0}}{2} \end{gathered}`

The solution

`\begin{gathered} \frac{-\text{ 2 + 0}}{2}\text{ or }\frac{-2\text{ - 0}}{2} \\ \\ (-2)/(2)\text{ or }(-2)/(2) \\ \\ -\text{ 1 or -1} \\ \end{gathered}`

Hence, the solution of the quadratic formula is - 1 (twice)