As given by the question,
There are given that the equation:
![4x+2y=20](https://img.qammunity.org/2023/formulas/mathematics/college/fyp238gz60zhpfz15r4n27k0a4bnzaj6j7.png)
Now,
First, suppose any number, for which the given equation has satisfied.
So, the number is, x = 2 and y = 6
Then,
Put both values into the given equation
![\begin{gathered} 4x+2y=20 \\ 4(2)+2(6)=20 \\ 8+12=20 \\ 20=20 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8tak9vbann1firervxb64zebmd5svb85fr.png)
Then,
Put the same value of x and y into the given option and check whether it is satisfied:
So,
From option 3:
![\begin{gathered} 2x+y=10 \\ 2(2)+6=10 \\ 4+6=10 \\ 10=10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/sewuycq6w15czymutmccj0ow99mhc14781.png)
Hence, the correct option is 3.