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Solve the quadratic equation 3x^2 - 2x = 4

User Toye
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\begin{gathered} 3x^2-2x=4​\Rightarrow3x^2-2x-4=0 \\ 3x^2-2x-4=0 \\ We\text{ cannot factorize so we will use the quadratic formula} \\ x=(-b\pm√(b^2-4ac))/(2a) \\ a=3,b=-2,c=-4 \\ \text{Plug that into the equation, we have:} \\ x=\frac{-(-2)_{}\pm\sqrt[]{(-2^2)-4(3)(-4)}}{2(3)} \\ x=\frac{2\pm\sqrt[]{4+48}}{6} \\ x=1.535183758488,-0.86851709182133 \\ x\approx1.54,-0.87 \end{gathered}

User Oscar Acevedo
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