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Please show me how to do a question like this.

Please show me how to do a question like this.-example-1

1 Answer

6 votes

Answer:


41.8\text{ KJ}

Step-by-step explanation:

Here, we want to get the amount of heat needed

Mathematically, we use the formula below:


\begin{gathered} Q\text{ = C}_p\text{ }* m\text{ }*\Delta T \\ Q\text{ = amount of heat} \\ C_p\text{ = specific heat capacity = 4.18 J/g}\degree C \\ m\text{ = mass = 200g} \\ \Delta T\text{ = change in temperature = 90-40 = 50}\degree C \end{gathered}

Now, we proceed to substitute the values as follows:


Q\text{ = 4.18 }*200\text{ }*50\text{ = 41800 J = 41.8 KJ}

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