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Find the 80th term of the following arithmetic sequence.14, 23, 32, 41,

User SnitramSD
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1 Answer

6 votes

Given data:

The firs term of AP is a=14.

The second term of AP is b=23.

The expression for the common difference is,

d=b-a

Substitute the given values.

d=23-14

=9

The expression for the 80th term is,


a_(80)=a+79d

substitute 14 for a, and 9 for d in the above expression.


\begin{gathered} a_(80)=14+79(9) \\ =725 \end{gathered}

Thus, the 80th term of AP is 725.

User SIMEL
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