Question

For all questions, assume that you have genes for beak color, tail-feather length, and feather color all linked (located) on the same chromosome, but you don't know the order of the genes on the chromosome or the distance between them. The alleles for these genes arebeak color: Y for yellow beak (YY and Yy) and y for black beak (yy)tail-feather length: L for long tail (LL and Ll) and l for short tail (ll)feather color: B for blue feathers (BB and Bb) and b for white feathers (bb)Cross a YyLl (heterozygous parent with dominant traits) with yyll (homozygous parent with recessive traits). Look at the number of genotypes of the F1 generation:YyLl: 400Yyll: 100yyLl: 100yyll: 400Which offspring are the recombinant offspring in this cross?How far apart are Y and L? Give your answer in map units. (Hint: Add the numbers of the two recombinant types, divide by the total number of offspring, and multiply by 100.)

Answer 1

offspring YyLl: 400, Yyll: 100, yyLl: 100 and yyll: 400

The recombinant offspring are allele combinations that are not directly inherited from the parents.

The parents combinations:YyLl and yyll,

The recombinant combinations: Yyll and yyLl

The other types are exacly like the parents so they are not recombinant.

answer: Yyll and yyLl