To answer this question we need to do a punnets square with the mentioned cross.
P: Tt x tt
The punnet square is as follows
![\begin{bmatrix}{-} & {T} & {t} \\ {t} & {Tt} & {tt} \\ {t} & {Tt} & {tt}\end{bmatrix}](https://img.qammunity.org/2023/formulas/biology/college/6xf82xfe029g4htrl37zm4ih0yvktwp8e9.png)
This way we have two heterozygous and two recessive homozygous, now we proceed to find these proportions. The correct answer is Tt,Tt,tt,tt.