Question

Write the equation of a line that passes through (-2, 0) and (3,10)

Answer 1

y = 2x + 4

Step-by-step explanation:

The equation of a line can be calculated using the following:

`y-y_1=m(x-x_1)_{}_{}`

Where m is the slope and it is equal to:

`m=(y_2-y_1)/(x_2-x_1)`

And (x1, y1) and (x2, y2) are two points of the line.

Then, replacing (x1, y1) by (-2, 0) and (x2, y2) by (3, 10), we get that the slope is:

`m=(10-0)/(3-(-2))=(10)/(3+2)=(10)/(5)=2`

So, the equation is:

`\begin{gathered} y-0=2(x-(-2))_{} \\ y=2(x+2) \\ y=2\cdot x+2\cdot2 \\ y=2x+4 \end{gathered}`

Therefore, the answer is y = 2x + 4