The front and back surfaces of the solid have the same area.
From the image, we see that the front surface is formed by 12 squares, each one with an area of 1 cm².
So, the areas of the front and back surface sum:
![12\operatorname{cm}+12\operatorname{cm}=24\operatorname{cm}^(2)]()
The right and left surfaces have the same area. And each one is formed by 8 squares of 1cm². So, the right and left surface areas sum:
![8\operatorname{cm}+8\operatorname{cm}=16\operatorname{cm}^(2)]()
And the up and down surfaces have the same area. Each one is formed by 6 squares of 1cm². So, the up and down surface areas sum:
![6\operatorname{cm}+6\operatorname{cm}=12\operatorname{cm}^(2)]()
Therefore, the total surface area of the solid is given by:
![24\operatorname{cm}+16\operatorname{cm}+12\operatorname{cm}=52\operatorname{cm}^(2)]()
Thus, the answer is:
![\mathbf{52\operatorname{cm}^(2)}]()