Question

The length of a rectangle is 6 yd longer than its width.

If the perimeter of the rectangle is 72 yd, find its length and width.

Answer 1

W = 15

Explanation:

(P)Perimeter = 2(L+W) or L+L+W+W

L means length

W means width

72=2((w+6)+w)

72=2(w+6+w)

72=2(2w+6)

72=4w+12

subtract 12 form both sides

72-12=4w+12-12

60=4w

60/4=4w/w

15=w