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Find the maximum value of Z = 5x + 2y and subject to the constraints: 2x + 2y ≥ 6, x ≥ 0, y ≥ 0.

Find the maximum value of Z = 5x + 2y and subject to the constraints: 2x + 2y ≥ 6, x-example-1
User Neuman
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1 Answer

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Looking at the constrains, we have that x and y must be positive values.

Also, if we divide the first inequality by two, we have that the sum of x and y must be greater than or equal 3.

Therefore, for the equation Z = 5x + 2y, the maximum value would be infinity, since the values of x and y can grow to any positive value and still satisfy the constrains.

If the question is asking "minimum value" instead of "maximum value", we can find it by using x = 0 and y = 3 (we choose the minimum possible value for x, because its coefficient in the equation Z = 5x + 3y is bigger, therefore it has the greater impact in the function value)

In this case, the minimum value of Z would be:


\begin{gathered} Z=5x+3y \\ x=0,y=3\colon \\ Z=5\cdot0+3\cdot3 \\ Z=9 \end{gathered}

There is no option for this value of Z.

So instead of calculating the minimum value, let's change the sign of the inequality 2x + 2y >= 6 for 2x + 2y <= 6.

In this case, we should maximize x, since it has the greater coefficient in the equation for Z.

So we should choose x = 3 and y = 0:


\begin{gathered} Z=5x+3y \\ x=3,y=0\colon \\ Z=5\cdot3+3\cdot0 \\ Z=15 \end{gathered}

Then, in this case, using the inequality 2x + 2y <= 6, the correct option would be the first one (15).

User Aeryaguzov
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