Question

Calculate the pressure in a 212 Liter tank containing 23300 g of argon gas at 25°C?

Answer 1

Step-by-step explanation

Given:

Volume, V = 212 L

Mass of argon = 23300 g

Temperature, T = 25°C = (25 + 273.15 K) = 298.15 K

What to find:

The pressure in the tank.

Step-by-step solution:

The pressure in the tank can be calculated using the ideal gas equation which is:

`PV=nRT`

n is the number of moles and can be also be:

`\begin{gathered} n=(m)/(M) \\ \\ Where\text{ }m=mass\text{ }and\text{ }M=molar\text{ }mass \end{gathered}`

Put n = m/M into the ideal gas equation above:

`PV=(m)/(M)RT`

The molar mass of argon = 39.948 g/mol

Put the values of the parameterss into the formula to get pressure, P:3