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What is the pressure of a balloon if it contains 1.6 moles of helium at a temperature of34°C and 950 mL?

What is the pressure of a balloon if it contains 1.6 moles of helium at a temperature-example-1

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Step-by-step explanation:

We have to determine the pressure inside a balloon that has a volume of 950 mL and contains 1.6 moles of He at 34 °C. To find the pressure we can use the ideal gas law formula.

P * V = n * R * T

P = n * R * T/V

Where P is the pressure, n is the number of moles, R is the ideal gas constant (R = 0.082 atm*L/mol*K), T is the temperature and V is the volume.

We already know the temperature in °C, the number of moles and the volume in mL. Before we find the answer to our problem we will have to convert the mL into L and the °C into K.

R = 0.082 atm*L/(mol*K)

n = 1.6 moles

T = (34 + 273.15) K

T = 307.15 K

V = 950 mL * 1 L/(1000 mL)

V = 0.950 L

Finally we can replace those values in the formula and get the answer to the problem.

P = n * R * T/V

P = 1.6 moles * 0.082 atm*L/(mol*K) * 307.15 K/(0.950 L)

P = 42.4 atm

Answer: the pressure is 42.4 atm.

User Max Gordon
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