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Determine the height of triangular faces.


\begin{gathered} h=\sqrt[]{(15)^2+((15)/(2))^2} \\ =\sqrt[]{225+56.25} \\ \approx16.77 \end{gathered}

Determine the surface area of figure.


\begin{gathered} S=2(15\cdot15+15\cdot15)+15\cdot15+4\cdot(1)/(2)\cdot15\cdot16.77 \\ =2(225+225)+225+503.1 \\ =1628.1 \end{gathered}

So surface area of figure is 1628.1 foot square.

Determine the volume of figure.


\begin{gathered} V=15\cdot15\cdot15+(15\cdot15\cdot15)/(3) \\ =3375+1125 \\ =4500 \end{gathered}

So volume of shape is 4500 foot cube.

User Jrennie
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